We’ve been seeing a lot of Zen 2 benchmarks lately, with pretty much all of them decimating their Intel competitors. We saw the Ryzen 5 3600 beating the Core i7-9700K, the Ryzen 7 3800X surpassing the Core i9-9900K, and last but not the least, the 16-core Ryzen 9 3950X became the fastest processor on Geekbench. But, what if I told you that an overclocked Ryzen 5 3600 can humiliate the Core i9-9900K? That’s right a $199 Zen 2 chip goes up against Intel’s ($484) consumer flagship and comes out on top:

Now, of course, terms and conditions apply. For starters, this benchmark was recorded on Linux where overclocking is easier and generally Geekbench scores are a bit higher, but not by this much. Sure, you can overclock a Core i9-9900K and get a notably higher score using LN2 and one of those expensive motherboards, but you are still looking at more than twice the investment for just the processor, plus the nitrogen cooling kit and a Z390 board. You can get a 3600 for just $200 plus an X470 motherboard should do just fine. Pair it with fast DDR4 memory and voila, you’ve got yourself a PC that beats an Intel system costing twice as much.

On top of this, the AMD setup has a default TDP rating of 65W while the Coffee Lake flagship draws 95W and is known to run hot. Furthermore, you’re also required to buy the heat-sink separately, so add another $35-50 (at the very least) to the blue setup. The Zen and Zen+ lineups might have been disruptive, forcing Intel to play nice, but the 7nm Zen 2 is aiming to bring it down.

Read more:

AMD Ryzen 3700X, The Best Overclocking Chip in Ryzen 3000 Series?

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10 COMMENTS

      • Right… I don’t think you understood the question. You’ve missed the point entirely. Where’s the proof for an overclocked CPU? We can only see the base frequency. I might call you a “retard” for not getting a simple question, but I don’t think that making such an obvious statement will make me feel any better. Feel free not to answer, is not as if I will expect something “illuminating” from you.

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